XDAG (Dagger) Solo Mining Calculator

Estimate how long it takes to solo mine a block of XDAG (Dagger) with your own hardware. BackPow combines the live Dagger network difficulty with your hashrate to compute the expected block time, the cumulative probability of finding a block over day, month and year, and the expected mining revenue in XDAG and USD.

XDAG network stats

How XDAG solo mining odds are calculated

Each hash is an independent attempt, so block discovery is memoryless and follows an exponential distribution. The average time to a block is T = network_hashrate ÷ your_hashrate × block_time. The chance of hitting at least one block within a period t is then given by the Poisson relation P = 1 − e^(−t/T) — the realistic probability, not a misleading linear one.

Frequently asked questions

How long does it take to solo mine one XDAG block?

It depends on your hashrate relative to the XDAG network hashrate (2.17 MH/s). Because hashing is memoryless, the time to find a block follows an exponential distribution: on average T = network_hashrate / your_hashrate × block_time. Enter your hashrate in the BackPow XDAG solo calculator to get the exact expected time.

What is the XDAG block reward?

The current XDAG block reward is 64 XDAG. BackPow tracks the 24h block reward and values a discovered block in both XDAG and USD using live market prices.

Is solo mining XDAG (Dagger) profitable?

Solo mining XDAG profitability depends on your hashrate, electricity cost and pool fees versus the block reward value and how often you expect to find a block. The BackPow calculator shows daily, monthly and yearly gross revenue and net profit so you can decide.

What algorithm does XDAG use?

XDAG (Dagger) uses the RandomX proof-of-work algorithm. You can mine it with any RandomX-capable ASIC, GPU or CPU listed in the BackPow hardware database.

What are the odds of finding a XDAG block?

BackPow models the cumulative probability of finding at least one block over a day, week, month or year with the Poisson formula P = 1 − e^(−t/T), giving a realistic chance instead of a naive linear estimate.

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